How Do You Solve This ‘rigid Object’-torque Problem? (it Doesn’t Give The Mass Of The Garden Tool)?
A gardening tool uses leverage from a hand to pull weeds. If a 1.3 N*m torque (about the pivot point) is required to pull a given weed, what force did the weed exert on the tool?
I know that you have to add the torque for the stick since the pivot is not in the middle (.13cm x weight of stick) but it still seems like I have 3 unknowns.
Here’s a diagram (the o is the pivot):
(Weed)–.04m–o———-.22m——-(F of hand)
I know this seems like quite alot but I have no clue how to break this problem. I’d appreciate it very much if I got the general process of solving this instead of the answer. Please and thanks!
You must assume that the mass of the tool can be neglected. Otherwise, they would have told you
.22 / .04 = 5.5 mechanical advantage
1.3 * 5.5 = 7.15 N